49 lines
1.0 KiB
C++
49 lines
1.0 KiB
C++
// 编写一个函数void str_bin(char str1[], char str2[])， str1、str2是两个有序字符串（其中字符按ASCII码从小到大排序），将str2合并到字符串str1中，要求合并后的字符串仍是有序的，允许字符重复。在main函数中测试该函数：从键盘输入两个有序字符串，然后调用该函数，最后输出合并后的结果。
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#include <bits/stdc++.h>
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using namespace std;
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void str_bin(char str1[], char str2[]);
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int main(int argc, char **argv) {
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char a[101], b[101];
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scanf("%s", a);
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scanf("%s", b);
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str_bin(a, b);
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puts(a);
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return 0;
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}
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void str_bin(char str1[], char str2[]) {
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char temp[202];
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int i = 0, j = 0, k = 0;
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while (str1[i] != '\0' && str2[j] != '\0') {
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if (str1[i] < str2[j]) {
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temp[k++] = str1[i++];
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}
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else if (str1[i] > str2[j]) {
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temp[k++] = str2[j++];
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}
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else {
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temp[k++] = str1[i++];
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temp[k++] = str2[j++];
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}
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}
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temp[k] = '\0';
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if (str1[i] != '\0') {
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strcat(temp, str1 + i);
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}
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else if (str2[j] != '\0') {
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strcat(temp, str2 + j);
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}
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strcpy(str1, temp);
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}
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